Optimal. Leaf size=129 \[ \frac{a^2 \tan (c+d x)}{d}-\frac{2 a^2 \cot ^5(c+d x)}{5 d}-\frac{5 a^2 \cot ^3(c+d x)}{3 d}-\frac{4 a^2 \cot (c+d x)}{d}-\frac{2 a^2 \csc ^5(c+d x)}{5 d}-\frac{2 a^2 \csc ^3(c+d x)}{3 d}-\frac{2 a^2 \csc (c+d x)}{d}+\frac{2 a^2 \tanh ^{-1}(\sin (c+d x))}{d} \]
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Rubi [A] time = 0.226338, antiderivative size = 129, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.381, Rules used = {3872, 2873, 3767, 2621, 302, 207, 2620, 270} \[ \frac{a^2 \tan (c+d x)}{d}-\frac{2 a^2 \cot ^5(c+d x)}{5 d}-\frac{5 a^2 \cot ^3(c+d x)}{3 d}-\frac{4 a^2 \cot (c+d x)}{d}-\frac{2 a^2 \csc ^5(c+d x)}{5 d}-\frac{2 a^2 \csc ^3(c+d x)}{3 d}-\frac{2 a^2 \csc (c+d x)}{d}+\frac{2 a^2 \tanh ^{-1}(\sin (c+d x))}{d} \]
Antiderivative was successfully verified.
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Rule 3872
Rule 2873
Rule 3767
Rule 2621
Rule 302
Rule 207
Rule 2620
Rule 270
Rubi steps
\begin{align*} \int \csc ^6(c+d x) (a+a \sec (c+d x))^2 \, dx &=\int (-a-a \cos (c+d x))^2 \csc ^6(c+d x) \sec ^2(c+d x) \, dx\\ &=\int \left (a^2 \csc ^6(c+d x)+2 a^2 \csc ^6(c+d x) \sec (c+d x)+a^2 \csc ^6(c+d x) \sec ^2(c+d x)\right ) \, dx\\ &=a^2 \int \csc ^6(c+d x) \, dx+a^2 \int \csc ^6(c+d x) \sec ^2(c+d x) \, dx+\left (2 a^2\right ) \int \csc ^6(c+d x) \sec (c+d x) \, dx\\ &=\frac{a^2 \operatorname{Subst}\left (\int \frac{\left (1+x^2\right )^3}{x^6} \, dx,x,\tan (c+d x)\right )}{d}-\frac{a^2 \operatorname{Subst}\left (\int \left (1+2 x^2+x^4\right ) \, dx,x,\cot (c+d x)\right )}{d}-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int \frac{x^6}{-1+x^2} \, dx,x,\csc (c+d x)\right )}{d}\\ &=-\frac{a^2 \cot (c+d x)}{d}-\frac{2 a^2 \cot ^3(c+d x)}{3 d}-\frac{a^2 \cot ^5(c+d x)}{5 d}+\frac{a^2 \operatorname{Subst}\left (\int \left (1+\frac{1}{x^6}+\frac{3}{x^4}+\frac{3}{x^2}\right ) \, dx,x,\tan (c+d x)\right )}{d}-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int \left (1+x^2+x^4+\frac{1}{-1+x^2}\right ) \, dx,x,\csc (c+d x)\right )}{d}\\ &=-\frac{4 a^2 \cot (c+d x)}{d}-\frac{5 a^2 \cot ^3(c+d x)}{3 d}-\frac{2 a^2 \cot ^5(c+d x)}{5 d}-\frac{2 a^2 \csc (c+d x)}{d}-\frac{2 a^2 \csc ^3(c+d x)}{3 d}-\frac{2 a^2 \csc ^5(c+d x)}{5 d}+\frac{a^2 \tan (c+d x)}{d}-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{-1+x^2} \, dx,x,\csc (c+d x)\right )}{d}\\ &=\frac{2 a^2 \tanh ^{-1}(\sin (c+d x))}{d}-\frac{4 a^2 \cot (c+d x)}{d}-\frac{5 a^2 \cot ^3(c+d x)}{3 d}-\frac{2 a^2 \cot ^5(c+d x)}{5 d}-\frac{2 a^2 \csc (c+d x)}{d}-\frac{2 a^2 \csc ^3(c+d x)}{3 d}-\frac{2 a^2 \csc ^5(c+d x)}{5 d}+\frac{a^2 \tan (c+d x)}{d}\\ \end{align*}
Mathematica [B] time = 0.945245, size = 317, normalized size = 2.46 \[ \frac{a^2 \cos (c+d x) \sec ^4\left (\frac{1}{2} (c+d x)\right ) (\sec (c+d x)+1)^2 \left (\csc (2 c) (216 \sin (c-d x)-416 \sin (c+d x)+624 \sin (2 (c+d x))-416 \sin (3 (c+d x))+104 \sin (4 (c+d x))-596 \sin (2 c+d x)-680 \sin (3 c+d x)+894 \sin (c+2 d x)+224 \sin (2 (c+2 d x))+894 \sin (3 c+2 d x)+480 \sin (4 c+2 d x)-776 \sin (c+3 d x)-596 \sin (2 c+3 d x)-596 \sin (4 c+3 d x)-120 \sin (5 c+3 d x)+149 \sin (3 c+4 d x)+149 \sin (5 c+4 d x)+320 \sin (2 c)-596 \sin (d x)+864 \sin (2 d x)) \csc (c+d x) \csc ^4\left (\frac{1}{2} (c+d x)\right )-3840 \cos (c+d x) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+3840 \cos (c+d x) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )}{7680 d} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.061, size = 202, normalized size = 1.6 \begin{align*} -{\frac{56\,{a}^{2}\cot \left ( dx+c \right ) }{15\,d}}-{\frac{{a}^{2}\cot \left ( dx+c \right ) \left ( \csc \left ( dx+c \right ) \right ) ^{4}}{5\,d}}-{\frac{4\,{a}^{2}\cot \left ( dx+c \right ) \left ( \csc \left ( dx+c \right ) \right ) ^{2}}{15\,d}}-{\frac{2\,{a}^{2}}{5\,d \left ( \sin \left ( dx+c \right ) \right ) ^{5}}}-{\frac{2\,{a}^{2}}{3\,d \left ( \sin \left ( dx+c \right ) \right ) ^{3}}}-2\,{\frac{{a}^{2}}{d\sin \left ( dx+c \right ) }}+2\,{\frac{{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}-{\frac{{a}^{2}}{5\,d \left ( \sin \left ( dx+c \right ) \right ) ^{5}\cos \left ( dx+c \right ) }}-{\frac{2\,{a}^{2}}{5\,d \left ( \sin \left ( dx+c \right ) \right ) ^{3}\cos \left ( dx+c \right ) }}+{\frac{8\,{a}^{2}}{5\,d\sin \left ( dx+c \right ) \cos \left ( dx+c \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.03421, size = 194, normalized size = 1.5 \begin{align*} -\frac{a^{2}{\left (\frac{2 \,{\left (15 \, \sin \left (d x + c\right )^{4} + 5 \, \sin \left (d x + c\right )^{2} + 3\right )}}{\sin \left (d x + c\right )^{5}} - 15 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 3 \, a^{2}{\left (\frac{15 \, \tan \left (d x + c\right )^{4} + 5 \, \tan \left (d x + c\right )^{2} + 1}{\tan \left (d x + c\right )^{5}} - 5 \, \tan \left (d x + c\right )\right )} + \frac{{\left (15 \, \tan \left (d x + c\right )^{4} + 10 \, \tan \left (d x + c\right )^{2} + 3\right )} a^{2}}{\tan \left (d x + c\right )^{5}}}{15 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.73451, size = 525, normalized size = 4.07 \begin{align*} -\frac{56 \, a^{2} \cos \left (d x + c\right )^{4} - 82 \, a^{2} \cos \left (d x + c\right )^{3} - 32 \, a^{2} \cos \left (d x + c\right )^{2} + 76 \, a^{2} \cos \left (d x + c\right ) - 15 \,{\left (a^{2} \cos \left (d x + c\right )^{3} - 2 \, a^{2} \cos \left (d x + c\right )^{2} + a^{2} \cos \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) \sin \left (d x + c\right ) + 15 \,{\left (a^{2} \cos \left (d x + c\right )^{3} - 2 \, a^{2} \cos \left (d x + c\right )^{2} + a^{2} \cos \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) \sin \left (d x + c\right ) - 15 \, a^{2}}{15 \,{\left (d \cos \left (d x + c\right )^{3} - 2 \, d \cos \left (d x + c\right )^{2} + d \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.47779, size = 184, normalized size = 1.43 \begin{align*} \frac{240 \, a^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 240 \, a^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) + 15 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - \frac{240 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1} - \frac{345 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 35 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 3 \, a^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5}}}{120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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